Derive The Derivative Of A Sine Function Using The Limit Definition

Learn how to derive the derivative of the sine function from first principles using the limit definition. Step-by-step proof and examples for calculus students.

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Understanding the Limit Definition of the Derivative

The derivative of a function f(x) at a point x is defined as the limit: f'(x) = lim_{h→0} [f(x+h) - f(x)] / h. For f(x) = sin(x), this becomes sin'(x) = lim_{h→0} [sin(x+h) - sin(x)] / h. To evaluate this, apply the sine angle addition formula: sin(x+h) = sin(x)cos(h) + cos(x)sin(h). Substituting gives [sin(x)cos(h) + cos(x)sin(h) - sin(x)] / h = sin(x)[cos(h) - 1]/h + cos(x)sin(h)/h.

Key Trigonometric Limits

The expression simplifies using standard limits: lim_{h→0} [cos(h) - 1]/h = 0 and lim_{h→0} sin(h)/h = 1. Thus, sin'(x) = sin(x) * 0 + cos(x) * 1 = cos(x). This rigorous proof relies on the squeeze theorem for sin(h)/h and geometric arguments for the cosine limit, confirming the derivative of sin(x) is cos(x).

Practical Example: Deriving at x = π/2

Consider x = π/2. Using the limit: lim_{h→0} [sin(π/2 + h) - sin(π/2)] / h = lim_{h→0} [cos(h) - 1] / h. This matches the cosine limit form, yielding 0, which is cos(π/2). For numerical verification, as h approaches 0 (e.g., h=0.001), [cos(0.001) - 1]/0.001 ≈ -0.0005, converging to 0.

Importance in Calculus and Applications

This derivation is foundational in calculus, establishing trigonometric differentiation rules used in physics (e.g., simple harmonic motion) and engineering (e.g., signal processing). It underscores the power of limits in proving fundamental theorems, avoiding memorization and enabling extensions to other functions like tan(x).

Frequently Asked Questions

What is the squeeze theorem's role in proving lim_{h→0} sin(h)/h = 1?
Why can't we use L'Hôpital's rule here?
How does this extend to cos(x)?
Is the derivative of sin(x) always cos(x), even for radians?