Solve Systems Of Linear Equations Using Substitution

Learn the step-by-step substitution method to solve systems of linear equations efficiently. Includes examples, common pitfalls, and practical applications for algebra students.

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What is the Substitution Method?

The substitution method solves a system of two or more linear equations by isolating one variable from an equation and substituting it into the others. This simplifies the system into a single equation with one variable, making it easier to find the solution. It's ideal for systems where one equation is already solved for a variable or can be easily rearranged.

Step-by-Step Process

First, solve one equation for one variable, say y in terms of x. Second, substitute that expression into the other equation to replace y. Third, solve the resulting equation for x. Fourth, plug the x-value back into the expression for y to find y. Finally, verify the solution by substituting both values into the original equations to ensure consistency.

Practical Example

Consider the system: y = 2x + 1 and 3x + y = 11. Substitute y from the first equation into the second: 3x + (2x + 1) = 11. Simplify to 5x + 1 = 11, so 5x = 10 and x = 2. Then y = 2(2) + 1 = 5. The solution is (2, 5), which satisfies both equations when checked.

Applications and Importance

This method is crucial in algebra for modeling real-world scenarios like budgeting or physics problems involving rates. It builds problem-solving skills and is foundational for advanced math like calculus. Common applications include economics for supply-demand equilibrium and engineering for circuit analysis.

Frequently Asked Questions

When should I use substitution over elimination?
What if the system has no solution using substitution?
What's a common mistake in substitution?